This might be very arduous to analyse for an arbitrary deck; however, your normal premise is appropriate. The variance anticipated by a deck with an arbitrarily giant variety of copies of every card (that’s, drawing randomly with
alternative) would have larger variance.
The next instance could be taken as an analogy for lands and non-lands in a deck.
For the sake of study we will take into account the next “deck”.
20x Black Lotus
40x Lightning Bolt
This deck will win when it casts 3 Black Loti and seven Lightning Bolts. It will occur on or after the tenth card is drawn, when that card is both the threerd Black Lotus or 7th Lightning Bolt.
The likelihood of profitable on i
th draw is:
PW(i) = PW_Bolt(i) + PW_Lotus(i)
With out Substitute
For the conventional model of the deck, this can take someplace between 10 and 43 attracts inclusive.
The place the possibility of drawing the 7th Bolt is:
PW_Bolt(i) = Methods to attract i-1 playing cards with 6 Bolts * Probability to attract Bolt
PW_Bolt(i) = Select(40,6)*Select(20,(i-1)-6)/Select(60,i-1) * (40-6)/(60-(i-1))
And the possibility of drawing the threerd Lotus is:
PW_Bolt(i) = Methods to attract i-1 playing cards with 2 Loti * Probability to attract Lotus
PW_Lotus(i) = Select(20,2)*Select(40,(i-1)-2)/Select(60,i-1)*(20-2)/(60-(i-1))
We will validate this likelihood calculation by checking that it sums to 1.
The anticipated attracts that this deck might want to win is:
E = sum[i*PW(i),{i,10,27}] = 11.97
And the variance is:
Var = sum[(E-i)^2*PW(i),{i,10,27}] = 4.5
With Substitute
There isn’t a certain on what number of attracts it might take to get the profitable mixture; however, the essential logic nonetheless holds.
The possibility of drawing the 7th Bolt is:
PW_Bolt(i) = Methods to attract i-1 playing cards with 6 Bolts * Probability to attract Bolt
PW_Bolt(i) = Select(i-1,6)*(2/3)^6*(1/3)^(i-1-6) * (2/3)
And the possibility of drawing the threerd Lotus is:
PW_Bolt(i) = Methods to attract i-1 playing cards with 2 Loti * Probability to attract Lotus
PW_Lotus(i) = Select(i-1,2)*(1/3)^2*(2/3)^(i-1-2) * (1/3)
This additionally provides to 1 within the restrict.
The anticipated attracts that this deck might want to win is just barely larger:
E = sum[i*PW(i),{i,10,27}] = 12.39
However the variance is far larger:
Var = sum[(E-i)^2*PW(i),{i,10,27}] = 7.32